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math-talks/fixed-point-theorem.md

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---
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layout: default
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title: Fixed Point Theorem
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permalink: /math-talks/fixed-point-theorem/
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toc: true
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---
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# Fixed Point Theorem: Why Must Something Stay Unchanged?
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Mathematical Analysis • Mathematical Foundations • Analysis & Applications
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---
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## Building Intuition: The Crumpled Map Problem
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A thought experiment that reveals a profound mathematical truth.
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### Imagine This Scenario
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You take a map, **crumple it up**, and place it back on the table. The map is now folded, wrinkled, and distorted in countless ways.
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### The Central Question
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Is there a point on the map that remains in the **exact same location** as before?
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### Mathematical Insight
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- **Intuition says:** Probably not — everything moved!
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- **Mathematics says:** Absolutely **YES**!
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There must exist at least one point that hasn't moved.
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---
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## Formal Definition: What is a Fixed Point?
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### The Mathematical Definition
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A point $x$ is called a **Fixed Point** if it satisfies: $f(x) = x$
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In other words: The point remains completely unchanged when the function $f$ is applied to it.
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- **Input equals Output**
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- **An "Anchor" Point**
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- **Invariant Under $f$**
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---
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## Concrete Example: $f(x) = x^2$
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Let's find the fixed points of a basic quadratic function.
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### Step-by-Step Solution
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1. **Set up the equation:** $f(x) = x$ $x^2 = x$
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2. **Rearrange:** $x^2 - x = 0$
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3. **Factor:** $x(x - 1) = 0$
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4. **Solution:** $x = 0$ or $x = 1$
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### Graphical Visualization
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![](/images/math-talk/fixed-point-theorem/y-equals-x-squared-fixed-points.png){: width="75%"}
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**Key Insight:** Fixed points occur where the curve $y = x^2$ intersects the line $y = x$ (shown in gold).
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---
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## The Challenge: The Key Question
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### What if the function is more complicated?
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- **Simple Cases:** For $f(x) = x^2$, we can solve algebraically. But what about functions without closed-form solutions?
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- **The Real Challenge:** Can we still **guarantee** that a fixed point exists, even when we can't find it explicitly?
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**We need a general theorem — not just examples!** (Existence Proof • General Guarantee • Universal Result)
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---
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## Foundation: Review: Intermediate Value Theorem (IVT)
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A powerful tool from calculus that we'll use as our foundation.
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### The IVT Statement
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If $f$ is **continuous** on $[a, b]$ and $f(a) \cdot f(b) < 0$ then there exists $c \in (a, b)$ such that $f(c) = 0$
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**Core Insight:** A sign change guarantees crossing zero.
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### Visual Intuition
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![](/images/math-talk/fixed-point-theorem/ivt-visual-intuition.png){: width="75%"}
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- Continuous curve from negative to positive.
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- Must cross the $x$-axis somewhere.
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---
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## Strategy: Reformulating the Problem
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The crucial transformation that connects fixed points to IVT.
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### The Key Transformation
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- **Original Problem:** $f(x) = x$
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- **Reformulated:** $f(x) - x = 0$
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### Why This Works
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Finding where $f(x) = x$ is equivalent to finding where $f(x) - x = 0$. This transforms a fixed point problem into a **root-finding problem**!
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### The Connection
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Now we can apply IVT! If we can show that $f(x) - x$ changes sign, a root (and thus a fixed point) must exist.
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---
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## Construction: Constructing a New Function
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Define the auxiliary function: $g(x) = f(x) - x$
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- **$g(x)$ Definition:** A new function that measures the **difference** between $f(x)$ and $x$.
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- **Root of $g(x)$:** If $g(c) = 0$, then $f(c) = c$.
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- **Fixed Point Found!** Finding a root of $g$ is equivalent to finding a fixed point of $f$.
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**Key Insight:** We've transformed the problem from "find where $f(x) = x$" to "find where $g(x) = 0$" — a classic root-finding problem solvable with IVT!
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---
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## Conditions: Applying the Conditions
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Setting up the boundary conditions for IVT.
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### Our Assumptions
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1. **Assumption 1:** $f(0) \geq 0$ (The function at 0 is non-negative)
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2. **Assumption 2:** $f(1) \leq 1$ (The function at 1 doesn't exceed 1)
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_Note: These are natural conditions for functions mapping $[0,1]$ into itself._
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### What This Means for $g(x)$
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- At $x = 0$: $g(0) = f(0) - 0 = f(0) \geq 0$
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- At $x = 1$: $g(1) = f(1) - 1 \leq 0$ (since $f(1) \leq 1$)
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**$g(x)$ changes sign from $\geq 0$ to $\leq 0$!**
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---
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## Application: Applying IVT to $g(x)$
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### By the Intermediate Value Theorem
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**Conditions Met:**
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- $g$ is continuous ($f$ is continuous)
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- $g(0) \geq 0$
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- $g(1) \leq 0$
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**IVT Conclusion:** Therefore, there exists some point $c \in (0, 1)$ such that: $g(c) = 0$
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We've proven that $g(c) = 0$ for some $c$ in $(0,1)$. But what does this mean for $f$?
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---
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## Conclusion: Fixed Point Exists!
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The final step that completes the proof.
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### The Final Deduction
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We know: $g(c) = 0$
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By definition of $g$: $f(c) - c = 0$
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Therefore: $f(c) = c$
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### Visual Proof
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![](/images/math-talk/fixed-point-theorem/g-c-equals-zero-fixed-point-proof.png){: width="75%"}
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**A FIXED POINT EXISTS!** The point $c$ where $g(c) = 0$ is exactly where $f(c) = c$.
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---
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## Interactive Example: $f(x) = \cos(x)$
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Does the cosine function have a fixed point?
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- **Does $f(x) = \cos(x)$ have a fixed point?** **Yes!**
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- **Reasoning:**
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1. **Continuity:** $\cos(x)$ is continuous everywhere.
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2. **Interval $[0, 1]$:** $\cos(0) = 1 \geq 0$, $\cos(1) \approx 0.54 \leq 1$.
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3. **Apply Theorem:** All conditions satisfied!
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**Fixed point exists in $[0, 1]$!**
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---
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## Interactive Example: $f(x) = 2x$
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A case where conditions matter!
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- **Does $f(x) = 2x$ have a fixed point in $(0,1)$?** **No!**
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- **Answer:** Only $x = 0$ is a fixed point, but it's not in $(0,1)$.
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- **Why Theorem Doesn't Apply:**
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- $f(0) = 0$ (satisfies $f(0) \geq 0$)
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- $f(1) = 2$ (**violates** $f(1) \leq 1$)
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- **The function maps $[0,1]$ outside itself!** At $x = 1$, $f(1) = 2$, which is outside the interval.
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**The conditions are crucial!**
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---
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## Critical Insight: Continuity is Crucial
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Without continuity, the guarantee disappears.
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### Why Continuity Matters
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If $f$ is **not continuous**, it can "jump" over the fixed point without ever hitting it.
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### Counterexample:
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$f(x) = x + 0.5$ for $x < 0.5$ $f(x) = x - 0.5$ for $x \geq 0.5$ This function has **no fixed point** because of the discontinuity at $x = 0.5$.
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### Visual Explanation
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![](/images/math-talk/fixed-point-theorem/discontinuity-no-fixed-point.png){: width="75%"}
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- **Continuous function:** must cross $y = x$.
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- **Discontinuous:** can jump over the line.
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---
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## Extension: Brouwer Fixed Point Theorem
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From 1D to 2D: A profound generalization.
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### The 2D Version
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- **The Setup:** Consider a **closed disk** (or any convex, compact set) in 2D. Let $f$ be a **continuous function** that maps the disk into itself.
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- **The Theorem:** Brouwer's Theorem states: $\exists p \text{ such that } f(p) = p$ At least one fixed point **must exist!**
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**Significance:** This extends to any finite dimension! It's one of the most important theorems in topology.
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---
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## Visualization: 2D Visualization: The Disk Transformation
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Any continuous transformation of a disk into itself has a fixed point.
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### The Crumpled Map Analogy (2D)
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Imagine taking a **circular disk**, crumpling it, stretching it, twisting it, and placing it back on top of itself.
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**The Question:** Is there a point that remains in exactly the same position? **Answer: YES!** Brouwer guarantees it.
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### Visual Intuition
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![](/images/math-talk/fixed-point-theorem/disk-transformation-visual.png){: width="50%"}
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No matter how you transform the disk, at least one point must stay fixed.
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---
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## Philosophy: The Beautiful Intuition
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### The Elegant Insight
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> "You cannot 'move everything' without leaving at least one point unchanged."
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- **Counterintuitive:** It seems like you should be able to move everything, but mathematics says otherwise.
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- **Universal:** This applies to ANY continuous transformation, no matter how complex.
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- **Profound:** This simple idea has applications across mathematics, economics, and physics.
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---
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## Application: Fixed Point Iteration
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A practical numerical method for solving equations.
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### The Iteration Method
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**THE RECURRENCE** $x_{n+1} = f(x_n)$
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- **How it works:** Start with an initial guess $x_0$, then repeatedly apply $f$. If the sequence converges, it converges to a fixed point!
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- **Visual:** The "staircase" or "cobweb" diagram shows how iteration converges to the fixed point where $y = f(x)$ intersects $y = x$.
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![](/images/math-talk/fixed-point-theorem/fixed-point-iteration-staircase-cobweb.jpg){: width="75%"}
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This turns equation-solving into simple iteration!
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---
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## Worked Example: Solving $x = \cos(x)$
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Using iteration to find the fixed point.
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### The Iteration Process
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- **Initial Value:** $x_0 = 0.5$
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- **Iteration Formula:** $x_{n+1} = \cos(x_n)$
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- **First few iterations:**
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- $x_1 = \cos(0.5) \approx 0.8776$
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- $x_2 = \cos(0.8776) \approx 0.6390$
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- $x_3 = \cos(0.6390) \approx 0.8027$
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- $x_4 = \cos(0.8027) \approx 0.6948$
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### Convergence Visualization
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![](/images/math-talk/fixed-point-theorem/cosine-fixed-point-convergence.png){: width="75%"}
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**Converges to $x \approx 0.7391$** This is the unique fixed point of $\cos(x)$!
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---
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## Theory: Why Iteration Works
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### Convergence Conditions
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- **When It Works:** Iteration converges to a fixed point under certain conditions: $\vert f'(x)\vert < 1$ near the fixed point
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- **The Intuition:** If the function is "flat enough" near the fixed point, each iteration gets closer:
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- Small derivative = small steps
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- Sequence approaches fixed point
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**Practical Value:** Fixed point iteration provides a simple, robust numerical method for solving equations that might be difficult to solve algebraically.
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---
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## Profound Application: Game Theory & Nash Equilibrium
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Where fixed point theorems changed economics forever.
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### The Nash Equilibrium
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- **Definition:** A set of strategies where no player can benefit by changing their strategy unilaterally.
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- **John Nash's Proof (1950):** Nash used **Brouwer's Fixed Point Theorem** to prove that **every finite game has at least one equilibrium!**
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- **Nobel Prize in Economics (1994)**
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- **Example:** Prisoner's Dilemma — both players confessing is the Nash Equilibrium, even though both would be better off cooperating.
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Fixed point theorems provide the mathematical foundation for modern game theory!
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---
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## Summary: Final Summary
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### Key Takeaways
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1. **Core Idea: Continuity $\Rightarrow$ Existence** A continuous function mapping $[0,1]$ into itself **must** have a fixed point.
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2. **The Strategy: Transform problem $\rightarrow$ Apply IVT** Rewrite $f(x) = x$ as $g(x) = f(x) - x = 0$, then use the Intermediate Value Theorem.
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3. **Generalization: Brouwer's Theorem** Extends to any dimension: Any continuous transformation of a disk into itself has a fixed point.
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4. **Applications: Wide-ranging impact** From numerical methods (fixed point iteration) to economics (Nash Equilibrium).
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**In a changing world, something always stays the same.**

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