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Copy pathq_101_symmetric_tree.cpp
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53 lines (51 loc) · 1.75 KB
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool isSymmetric(TreeNode* root) {
// Iterattive ===============================================================
if (root == nullptr) {
return true;
}
stack<TreeNode*> s_left, s_right;
auto i_left = root, i_right = root;
while (s_left.size() > 0 || s_right.size() > 0 || i_left != nullptr || i_right != nullptr) {
if (s_left.size() != s_right.size()) {
// cout << "stack size diff" << endl;
return false;
}
if ( (i_left == nullptr && i_right != nullptr)
|| (i_left != nullptr && i_right == nullptr) ) {
// cout << "current node null mismatch" << endl;
return false;
}
if (i_left != nullptr) {
s_left.push(i_left);
s_right.push(i_right);
i_left = i_left->left;
i_right = i_right->right;
} else {
i_left = s_left.top();
i_right = s_right.top();
if (i_left->val != i_right->val) {
return false;
}
// cout << i_left->val << ",";
s_left.pop();
s_right.pop();
i_left = i_left->right;
i_right = i_right->left;
}
}
return true;
}
};