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Ensure new type is repr(transparent) - #318
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The immediately following code performs a cast from the new type to the old type, which `repr(transparent)` guarantees the safety of. I'm not convinced this is _guaranteed_ to be safe with the default `repr(Rust)`.
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Yeah I think you're correct. Thanks! |
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The immediately following code performs a cast from the new type to the old type, which
repr(transparent)guarantees the safety of. I'm not convinced this is guaranteed to be safe with the defaultrepr(Rust).