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Classify constant insertions after stage-1 E_22 and stage-2 E_11 (no κ) - #282
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Prove which constant F_2 pairs make the e coefficient equal the pure product in those two gaps of the nine-gate diagonal word. The solution set has size 2^30 and is not the stage-0 E_22 / stage-1 E_11 set. No kappa change. Co-authored-by: unpaidmoon <unpaidmoon@users.noreply.github.com>
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In the nine diagonal gates of the PR CrocSwap#7027 word, constant
F_2matrices in the gap after stage-1E_22and the gap after stage-2E_11make the coefficient ofeequal the pure product for exactly2^30pairs. The matched positions are the off-diagonal pairs inside{4, 5}and{1, 2, 3, 6, 7}. Every such coefficient has diagonal entries in{0, P_ii}, and none equalsI. No kappa change. Selected κ stays363005817/100000000000.Change and mathematical scope
Proof, in
F_2[x, y, z][e]/(e^2), of the constant solution set for those two slots. The middle diagonal isdiag(1+z, 1, 1, 1, 1+y, 1+y, 1, 1). The count2^30agrees with PR CrocSwap#7215, and the solution set does not:(1, 4)is free there and blocked here, while(1, 2)is blocked there and free here. This is not a caller, a native bill, a word forg=13org=31, or a selected-frontier change. Polynomial entries and every other slot pair remain open.Task and overlap
Base: canonical main
e54523517d0f03e58352e647c403a5af3e525a57, priority revision 8. Live selected recordcertificates/selected-result.jsonis363005817/100000000000.current-priorities.mdon that base still prints0.00310045; this package does not edit it.Card:
joint-query-controller, scope changed. The card asks whether a changed query demand removes real work. This package takes the first open question of PR CrocSwap#7215, which is the constant classification of the two later gaps in the same nine-gate word.Ordered eligible list for session r270, after excluding structured CrocSwap#1166 handoffs whose next tasks are already delivered and excluding open-next bullets that a later unpaidmoon PR answers or refines:
R+S+T+U = 4I-E-F-Gwith at least four odd-clabels. PR Prove a no-edge pattern-dimension-4 pool has total image at most 6. CrocSwap/integer-mult-bounds#7139's first two bullets are answered by Exhibit an irreducible no-edge image of dimension 7 at pattern dimens… CrocSwap/integer-mult-bounds#7237 and Show two dimension-6 no-edge pools outside the three printed coordina… CrocSwap/integer-mult-bounds#7221, and its third bullet only points back at question 1 of Prove the no-edge irreducible joint-image bound is 3. CrocSwap/integer-mult-bounds#6921.F_2pairs after stage-1E_22and stage-2E_11. This package.Nearest records: PR CrocSwap#7215 classifies the previous pair and leaves this one. PR CrocSwap#7103 classifies the adjacent stage-0 pair. PR CrocSwap#7191 classifies polynomial entries in that stage-0 pair. PR CrocSwap#7039 is the one-insertion diagonal obstruction. GitHub search on 2026-11-11 found no PR whose title states these two slots. The degree-at-most-1 question left by CrocSwap#7215 for its own slots is not taken.
Validation
Python 3.12, standard library only, from the repository root:
Both the normal and
-Ocommands printPASS_STAGE1_E22_STAGE2_E11_GAPS, withmatched_off_diagonal 22,blocked_off_diagonal 34,solution_pairs 2^30,witness_both_nonzero 3, andcoefficient_equals_I 0. The registered metadata check passed. The2^30matrices are not enumerated: each of the 64 positions has a four-element bit equation, solved exhaustively, and the equations separate. Controls reject(1, 4), an unequal matched bit, a mixed matched-plus-blocked pair, and(I, I). Predecessor replays, Lean, Docker, and the selected cold replay were not run.Credit
The paired-star contract is PR CrocSwap#5747 (Ali Romman), with PR CrocSwap#5673, PR CrocSwap#5631, and PR CrocSwap#5617. The nine-gate word is PR CrocSwap#7027. The one-insertion obstruction is PR CrocSwap#7039. The adjacent stage-0 classification is PR CrocSwap#7103. Polynomial entries in that pair are PR CrocSwap#7191. The question taken here is the first open question of PR CrocSwap#7215, head
e1656a671fffddcd0b9ad07d500825686ff852ae.Prepared by unpaidmoon with substantial Cursor Grok assistance. Independent human review and a proof-assistant proof are unclaimed. Apache-2.0.
Open next questions
C = Pbeyond the2^30constant pairs? At the blocked position(1, 4),R_{1,4} = 1andS_{1,4} = 1+ysolves that one entry. First step: keep a legal constant diagonal and legal matched bits, substitute that pair, and multiply againstP. Nothing external blocks it. This is not the polynomial question PR Classify polynomial two-gap insertions with exact dimension 64d+50 (no κ) CrocSwap/integer-mult-bounds#7191 answered for the stage-0 gaps, and not the same question PR Classify constant insertions after stage-0 E_22 and stage-1 E_11. CrocSwap/integer-mult-bounds#7215 left for its own slots.C = Pafter stage-2E_22and after the stage-2 leaf gate? TheE_22-then-next-E_11series stops at stage 2. First step: the diagonal of the single gate between those slots.Workflow feedback (optional)
CrocSwap#1200